Re: Exact Trisecting

Re: Exact Trisecting
Posted: Jul 26, 2005 2:25 AM Plain Text Reply




quasi wrote:
> Bassam Karzeddin wrote:
>
> > An arbitrary angle and its exact trisection angle
> > fits exactly in the following symbolic triangle with the following sides:
> > a^3 , a*(b^2-a^2) , b*(b^2-2*a^2)
> > Where : 2 >= b/a >= sqrt(2)
> > (a,b):are positive real numbers
>

And,iff, 2>= b/a >= F,Then: a*(b^2-a^2) >= b*(b^2-2*a^2)
Where : F is a Fibonacci Number (F=1.618033989...)

Bassam Karzeddin
Al Hussein Bin Talal University
Jordan
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