Re: a curious integral
- From: Narcoleptic Insomniac <i_have_narcoleptic_insomnia@xxxxxxxxx>
- Date: Tue, 26 Jul 2005 13:05:55 EDT
On Jul 26, 2005 10:35 AM, bugalore@xxxxxxxxxxx wrote:
> Hello,
>
> Can anyone suggest how to evaluate the following
> integral:
>
> > Int(1/v/sqrt(v^2*a+b*v+c), v);
>
> /
> | 1
> | ---------------------- dv
> | 2
> / v sqrt(v a + b v + c)
>
>
> Maple finds a surprisingly clean/simple answer:
>
> > value(%) assuming c>0;
>
> 2 c + b v
> arctanh(1/2
> arctanh(1/2 ------------------------)
> 1/2 2 1/2
> c (v a + b v + c)
> -
> - -------------------------------------
> 1/2
> c
>
> I'm trying to understand where the "2c+bv" comes
> from....
>
> thanks,
> bugalore.
>
Maybe it's just me, but I cannot decypher what the original intgral even is. Like when you say
Int[1/v/sqrt(v^2*a+b*v+c)]
do you mean the root quantity to be
v^2 * (a+b) * (v+c)
or do you mean it to be
av^2 + bv + c.
Also, it's really hard to tell when you try to draw it out. Moreover, when you did try to draw it out the quantity under the root became a first degree polynomial, instead of a second degree that you originally had.
Confused,
Kyle
.
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