Re: Bizarritudes

In article <27310094.1122313371102.JavaMail.jakarta@xxxxxxxxxxxxxxxxxxxxxx>,
bischar <bisch_a_r@xxxxxxxx> wrote:
>In (pi+1)/pi there are lots of 8 it seems.

(pi+1)/pi = 1 + 1/pi. The 1 doesn't supply any 8's, so you're talking
about 1/pi. In the first 100000 digits the number of occurrences of
the digits 0 to 9 are
10099, 10011, 9954, 9878, 10199, 9840, 9986, 9972, 9997, 10065
respectively. So there's very close to the expected number of 8's,
as well as each of the other digits. Nothing that looks at all
nonrandom.

Robert Israel israel@xxxxxxxxxxx
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada
.

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