Re: Bizarritudes

> In article
> <27310094.1122313371102.JavaMail.jakarta@xxxxxxxxxxxxx
> forum.org>,
> bischar <bisch_a_r@xxxxxxxx> wrote:
> >In (pi+1)/pi there are lots of 8 it seems.
>
> (pi+1)/pi = 1 + 1/pi. The 1 doesn't supply any 8's,
> so you're talking
> about 1/pi. In the first 100000 digits the number of
> occurrences of
> the digits 0 to 9 are
> 10099, 10011, 9954, 9878, 10199, 9840, 9986, 9972,
> 9997, 10065
> respectively. So there's very close to the expected
> number of 8's,
> as well as each of the other digits. Nothing that
> looks at all
> nonrandom.
>
> Robert Israel
> israel@xxxxxxxxxxx
> Department of Mathematics
> http://www.math.ubc.ca/~israel
> University of British Columbia Vancouver,
> BC, Canada

Maybe we should calculate the respective agglutination rate of the digits 0 to 9, if I can express it so :)
.

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