Re: Creating functions for Kabbalah




CoreyWhite@xxxxxxxxx wrote:
> If I say one = 72058143793758208 two = 73787257769815441408 three =
> 324518558494720301052040015511552
>
> How would I define f:(1,2,3)->(one,two,three) that maps 1->one, 2->two,
> and 3->three ?
>
> I've created a code that gives every word, phrase, and letter in the
> english language a unique number.. I'm trying to create function now
> that produce meaninfull relationships within the language..

Good luck. There are isolated examples using isolated methods; the most
common one is

ELEVEN + TWO - ONE = TWELVE.

This works out okay mathemtically. But now, write down the letters in
ELEVEN, write down the letters in TWO, and cross out the letters in
ONE. If you rearrange the letters you have left, you can spell out
TWELVE.

Here's another exercise for you. Prove that there is no function f
mapping letters of the alphabet to real numbers such that each of the
number names from 1 to 9 in English adds up to its value.

That is, show that it's impossible to have

f(O) + f(N) + f(E) = 1
f(T) + f(W) + f(O) = 2
....
f(N) + f(I) + f(N) + f(E) = 9

at the same time. It's actually not too difficult.

> It is like Kabbalah that actually works.

Do you actually believe that? Do you really believe that Hebrew is a
language which was CREATED by Number Theorists? (Especially in light of
the puzzle I gave you?)

A few years ago, I thought about what Kabbalah and came up with the
conclusion that one of three things must be true, in order for it to
work:

(1) Hebrew really works, which means it was created by number
theorists;
(2) There are some coincidences, but most of Kabbala is a stretch; and
(3) It's a joke that Jews decided to play on the world.

> "Just use a base 26 system: Let A = 0, B = 1, C = 2, ..., Z = 25,
> then assign to the word a_1 a_2 a_3 a_4 ... a_k the number
>
> a_1 + 26 a_2 + 26^2 a_3 + ... + 26^(k-1) a_k.
>
>
> You can also use an encoding based on factorization. For instance, you
> can encode the finite sequence of numbers a_1, a_2, a_3, a_4, ..., a_k
> as
>
> 2^(a_1) * 3^(a_2) * 5^(a_3) * 7^(a_4) * ... * (kth prime)^(a_k),
>
> and the outcome will be unique. " --- Christopher Heckman

Things similar to what you want to do have been done -- for instance,
there is a way to assign numbers to letters to make HITLER add up to
666 -- but again, it's an ad-hoc thing; nothing works universally.

--- Christopher Heckman

.



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