Re: help polylogarithm



wissam wrote:
dear Raymond,
thank you  very much for your help.
as for the homework, i already did it and everything is alright.
in the integral that i showed to you in my last question, what does the presence of the imaginary term in my integral mean? is it a sign that i have something wrong ? can i remove this imaginary term in the final answer?

Ok I got this one too! The answer to 3 digits is -0.2056167583561 + 0.5443965225759*I corresponding to -zeta(2)/8 + log(2)*Pi/4*I

  Enjoy!
	   Raymond


(cracked by this gp 'simple product recognizer' : a= 0.5443965225759 lindep([log(a),1,log(2),log(3),log(5),log(7),log(11),log(Pi),log(log(Pi)),log(log(2)),log(log(3)),log(Euler),log(zeta(3)),log(zeta(5)),log(sinh(Pi))],13) )

.



Relevant Pages

  • Re: help polylogarithm
    ... as for the homework, i already did it and everything is alright. ... in the integral that i showed to you in my last question, what does the presence of the imaginary term in my integral mean? ... the upper bound for x is 1/2 instead of 1 ...
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  • Re: help polylogarithm
    ... as for the homework, i already did it and everything is alright. ... in the integral that i showed to you in my last question, what does the presence of the imaginary term in my integral mean? ... Prev by Date: ...
    (sci.math)
  • Re: help polylogarithm
    ... wissam wrote: ... > in the integral that i showed to you in my last question, what does the presence of the imaginary term in my integral mean? ... an error in your computations or in the given integral (remember the missing ']') ... the upper bound for x is 1/2 instead of 1 ...
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  • Re: help polylogarithm
    ... dear raymond ... the imaginary term that we have in your last answer, ... Prev by Date: ...
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