Re: help polylogarithm

wissam wrote: 
dear raymond
the imaginary term that we have in your last answer, could it be removed? or we should keep it for some reason!!!!?
thank you
wissam

I fear you missed one of my answers (dated 17/08) I'll reproduce it here (lightly edited) :

wissam wrote:

> dear Raymond,
> thank you very much for your help.
> as for the homework, i already did it and everything is alright.
> in the integral that i showed to you in my last question, what does the presence of the imaginary term in my integral mean? is it a sign that i have something wrong ? can i remove this imaginary term in the final answer?


I fear you can't remove it (this is a consequence of the polylog parameter that becomes greater than 1).
Some hypothesis :
- an error in your computations or in the given integral (remember the missing ']')
- the upper bound for x is 1/2 instead of 1
- an error in my computations (:-) unlikely since I got the numerical values using two different 'independant' tools)
- there's one or more terms in your problem with a complementary imaginary part so that the final result is real
- the result is not real and it's right (who knows?)
- ....

  Fine verifications!
                Raymond
.

Relevant Pages

  • Re: help polylogarithm
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    (sci.math)
  • Re: help polylogarithm
    ... dear raymond ... the imaginary term that we have in your last answer, ... Prev by Date: ...
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  • Re: help polylogarithm
    ... as for the homework, i already did it and everything is alright. ... in the integral that i showed to you in my last question, what does the presence of the imaginary term in my integral mean? ... the upper bound for x is 1/2 instead of 1 ...
    (sci.math)
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