Re: true or false: (x^5 - x) has inflexion point at origin, (x^4 - x) doesn't
- From: "N. Silver" <mathelp@xxxxxxxxxxxxxxxx>
- Date: Thu, 25 Aug 2005 18:16:05 GMT
John Ramsden wrote:
> Is there any practical purpose in distinguishing a "change
> of sign in curvature" point from a straightforward y'' = 0
> point, apart from simply describing the appearance of
> curves?
Thinking of y' as velocity and y" as acceleration
gives us a "practical" application of inflection points.
.
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- true or false: (x^5 - x) has inflexion point at origin, (x^4 - x) doesn't
- From: David Jones
- Re: true or false: (x^5 - x) has inflexion point at origin, (x^4 - x) doesn't
- From: Robert Israel
- Re: true or false: (x^5 - x) has inflexion point at origin, (x^4 - x) doesn't
- From: Gerry Myerson
- Re: true or false: (x^5 - x) has inflexion point at origin, (x^4 - x) doesn't
- From: john_ramsden
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- From: Robert Israel
- Re: true or false: (x^5 - x) has inflexion point at origin, (x^4 - x) doesn't
- From: john_ramsden
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