Re: A set containing a nonempty open interval
- From: klewis@xxxxxxxxxxxxxxxx (Keith A. Lewis)
- Date: Fri, 26 Aug 2005 20:37:42 +0000 (UTC)
A N Niel <anniel@xxxxxxxxxxxxxxxxxxxxx> writes in article <260820051428574700%anniel@xxxxxxxxxxxxxxxxxxxxx> dated Fri, 26 Aug 2005 14:28:57 -0400:
>In article <denmfc$o5k$1@xxxxxxxxxxxxxxxxxxx>, Keith A. Lewis
><klewis@xxxxxxxxxxxxxxxx> wrote:
>
>> "Amanda" <sca18@xxxxxxxxxxx> writes in article
>> <1125067955.450481.88600@xxxxxxxxxxxxxxxxxxxxxxxxxxxx> dated 26 Aug 2005
>> 07:52:35 -0700:
>> >
>> >I'd like some hints on how to prove that, if a set S has positive
>> >Lebesgue measure, then (A + A)/2 = {(x + y)/2 | x and y are in A}
>> >contains a non-empty open interval.
>>
>> Unless you specify x <> y, you might get all closed intervals.
>
>By "contains a non-empty open interval" he means it has a subset which
>is a non-empty open interval.
Since every interval has a subset which is an open interval, I wonder why
the word "open" is even in the question. Probably not important, I guess.
--Keith Lewis klewis {at} mitre.org
The above may not (yet) represent the opinions of my employer.
.
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