Re: Possible combinations

quasi wrote:
> With so few choices, you should at least try to get the answer
> experimentally. Just write out all the possible arrangements and
> actually count them. This will lead you to the general principle.
>

You are right. With the variables:

a = 0 or 1 or 2
b = 0 or 1

The formula appears to be:

(3 pow1) * (2 pow1) = 6 combinations;

With the variables:

a = 0 or 1 or 2
b = 0 or 1
c = 0 or 1

The formula appears to be:

(2 pow2) * (3 pow1) = 12 combinations.


Is this correct?


Regards,
JW



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