Re: Possible combinations

On Sun, 28 Aug 2005 17:22:39 +0200, "Janwillem Borleffs"
<jw@xxxxxxxxxxxxx> wrote:

>quasi wrote:
>> With so few choices, you should at least try to get the answer
>> experimentally. Just write out all the possible arrangements and
>> actually count them. This will lead you to the general principle.
>>
>
>You are right. With the variables:
>
>a = 0 or 1 or 2
>b = 0 or 1
>
>The formula appears to be:
>
>(3 pow1) * (2 pow1) = 6 combinations;
>
>With the variables:
>
>a = 0 or 1 or 2
>b = 0 or 1
>c = 0 or 1
>
>The formula appears to be:
>
>(2 pow2) * (3 pow1) = 12 combinations.
>
>
>Is this correct?
>
>
>Regards,
>JW
>

Yes, it's correct.
.

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