Re: Cardinality of Real Numbers
- From: "NotP" <spam@xxxxxxxx>
- Date: Sun, 28 Aug 2005 17:59:25 GMT
<jswimr3@xxxxxxxxx> wrote in message
news:1125251641.615664.93900@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> I've been thinking about cardinality proofs lately, and I've run into
> something that's been bothering me. I thought of what seems like a
> mapping from the set of integers to the set of real numbers. Now, of
> course, this can't exist, so there must be something wrong with my
> mapping, but I can't see what it is.
>
> The mapping works like this: for each integer, map it onto all the
> reals you can get by putting a decimal point anywhere in it. For
> example, 123 would map to:
>
> 123
> 12.3
> 1.23
> .123
>
> It seems like this would cover the full set of real numbers. Each of
> these mapped sets of reals is finite, and there would be a countable
> number of these sets, since the integers are countable. So this would
> seem to be a countable union of finite sets, which would, itself, be
> countable.
>
> I was wondering if perhaps I run into trouble with real numbers like
> .00000123, which wouldn't correspond to an integer in my scheme. But
> it seems like you could get around that by making a new rule, for
> example, that real numbers which begin with 1 would map to the numbers
> they would normally map to, but would also map to decimals where the 1
> is turned into a zero. So 10000123 would map to all the numbers it
> normally maps to, and would also map to .00000123. There would still
> be a finite number of real numbers for each integer.
>
> But the real numbers aren't countable. So where did I go wrong?
1. every number you "map to" is rational.
2. you do not even "map to" all of the rationals. (what about
..33333333333.... = 1/3? )
.
- References:
- Cardinality of Real Numbers
- From: jswimr3
- Cardinality of Real Numbers
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