Re: simple complex number query

From: boi <boi@xxxxxxxxxxx>
Date: Tue, 30 Aug 2005 08:55:19 +0200

On Tue, 30 Aug 2005 14:37:18 +0800, wrote:

> Hi,
>
> I am trying to prove that /A/B = /(AB) where A and B are complex numbers.
>
> assuming /(a + ib) = (a - ib)
>
> (a + ib)(c + id) -> AB
> = ac + i(ad+bc) -bd
> = (ac-bd) + i(ad + bc)
> so /((ac-bd) + i(ad + bc)) -> /(AB)

So ((ac-bd) - i(ad+bc)) = /(AB)

> /(a+ib)*/(c+id) -> /A/B
> = (a - ib)(c - id)
> = ac - iad - icb - bd
> = (ac - bd) - i(ad + bc) -> /A/B
>
> so /(AB) != /A/B which I know is not the case
>
> What have I done wrong here?

Nothing really
.

References:
- simple complex number query
  - From: .

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