Re: number sequence
- From: Virgil <ITSnetNOTcom#virgil@xxxxxxxxxxx>
- Date: Tue, 30 Aug 2005 21:49:23 -0600
In article <1125444724.556236.207670@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
"Russ" <rwpatterson@xxxxxxx> wrote:
> Hi:
>
> How should I go about trying to determine the equation that results in
> a number sequence like this:
>
> 2, 6, 22, 86, 342...
>
> I see the difference between each term is a power of 2 but am stuck on
> how to determine equation. e.g. difference between 86 and 342 is 2^8.
>
> thanks,
> russ
You could represent it by a recursion formula:
a_0 = 2 and a_n = a_(n-1) + 4^n.
At least as far as the terms shown go.
.
- References:
- number sequence
- From: Russ
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