Re: sum of zetas
- From: "Jon Slaughter" <Jon_Slaughter@xxxxxxxxxxx>
- Date: Wed, 7 Sep 2005 05:13:33 -0500
"Gottfried Helms" <helms@xxxxxxxxxxxxx> wrote in message
news:dfmbv1$s4o$04$1@xxxxxxxxxxxxxxxxxxxx
> Can the sum
>
> x = sum zeta(2^(2^i) ) = zeta(2) + zeta(4) +zeta(16) + zeta(256) + ...
> i=0
>
> be given in a more simple form in common functions?
>
> Gottfried Helms
Well, if your sum is infinite then the series divergs(Zeta(k) > 1 for k > 1)
but if it is finite then yes, you can write it much simpiler and in closed
for since Zeta(2k) is known for all k > 1.
Jon
.
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