Re: Limits and e

Joseph Fagan wrote:
>
> Limit[(1+1/n)^nx] as n->inf = Limit[(1+x/n)^n] as n->inf
>
> Can anyone give me a reference.
> Both limits are e^nx

I think the "n" in "e^nx" is a typo. Since "n->inf" is a variable
binding operator, "n" can't appear free as well.

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