Re: 1/89 and the Fibonacci sequence-
- From: JEMebius <jemebius@xxxxxxxxx>
- Date: Wed, 07 Sep 2005 21:43:00 +0100
Not necessary to stay silent about the 1/89 mystery and related mysteries:
Try and explore power series developments like...
1/(1 - x - x^2) = 1 + x + 2x^2 + 3x^3 + 5x^4 + ..., which gives 1/0.89 = 1.1235... and 1/0.9899 = 1.0102030509....
You will see the Fibonacci numbers being generated when you develop the power series, and you will see them to fall into place when you multiply out the identity
1 = (1 - x - x^2)(1 + x + 2x^2 + 3x^3 + 5x^4 + ...)
1/(1 - x) = 1 + x + x^2 + x^3 + ..., which gives 1/0.98 = 1.020408163265.... and 14/0.98 = 100/7 = 14.285714....; 1/0.998 = 1.002004008016032064128256513...; 1/0.997 = 1.003009027083...
All power series developments of reciprocals of polynomials yield recurrent relations for the coefficients.
Cheers - Johan E. Mebius
Dan wrote:
>Sorry about the multiple posts but this was >a bitch to edit! > >The mystery of 1/89 and the Fibonacci sequence > > >1/89 = >01123595505617977528089887640449438202247191/ >01123595505617977528089887640449438202247191/ >01123595505617977528089887640449438202247191/ >01123595505617977528089887640449438202247191/ >01123595505617977528089887640449438202247191/ >01123595505617977528089887640449438202247191/ >01123595505617977528089887640449438202247191/ >01123595505617977528089887640449438202247191/ >01123595505617977528089887640449438202247191/ >01123595505617977528089887640449438202247191/ >.. >With a continuing decimal expansion that has >a period of 44. > >Then adding the Fibonacci sequence in this manner -- >***OOPs- fixed below*** >0112358 > >>>>>+13 >>>>>+>21 >>>>>+>>34 >>>>>+>>>55 >>>>>+>>>>89 >>>>>+>>>>144 >>>>>+>>>>>233 Which creates a right >>>>>+>>>>>>377 one step offset. >>>>>+>>>>>>>610 >>>>>+>>>>>>>>987 >>>>>+>>>>>>>>1597 >>>>>+>>>>>>>>>2584 >>>>>+>>>>>>>>>>4181 >>>>>+>>>>>>>>>>>6765 >>>>>+>>>>>>>>>>>10946 >>>>>+>>>>>>>>>>>>..... etc. > >---------------------------------- >01123595505617977528089887640449438202247191... >= 1/89? > >Will this continue repeating the period of 1/89 >no matter how many fibonacci numbers are added >in this manner? > >If it does, can it be proved? > >Others like 1/80 can be represented as -- >The sequence of -- 0,1,2,4,8,16,32,64,128... > >>.01248 >>+>>16 >>+>>>32 >>+>>>>64 >>+>>>>128 >>+>>>>>256 >>+>>>>>>512 >>+>>>>>>1024 >>+>>>>>>>2048 >>+>>>>>>>>4096 >>+>>>>>>>>>8192 >>+>>>>>>>>>16384 >>+>>>>>>>>>>32768 >>+>>>>>>>>>>>65536 >>+>>>>>>>>>>>>...... etc. > >---------------------------------- >=.0124999999999999999999999999999... >or .0125 = 1/80 > >Another is the silver mean sequence where the difference >between terms converges on sqrt(2)+1. Found in (OEIS) A000129. > >0,1,2,5,12,29,70,169,408,985,2378,5741,13860,33461... > >Then 1/79 represents the adding together below. > >0125 >+>>12 >+>>>29 >+>>>>70 >+>>>>169 >+>>>>>408 >+>>>>>>985 >+>>>>>>2378 >+>>>>>>>5741 >+>>>>>>>13860 >+>>>>>>>>33461 >+>>>>>>>>>80782 >+>>>>>>>>>195025 >+>>>>>>>>>>470832 >+>>>>>>>>>>1136689 >+>>>>>>>>>>>2744210 >+>>>>>>>>>>>>6625109 >+>>>>>>>>>>>>15994428 >+>>>>>>>>>>>>>........ etc. >--------------------------------------------------- >0126582278481012658227848101265822784810126582278481... >= 1/79 having a period of 13. > >1/69 is this sequence added in the above manner. >0,1,3,10,33,109,360,1189,3927,12970,42837,141481,467280... >In OEIS as A006190. > >1/59 also in OEIS as sequence A0010076 > >If all this is true, what is the sequence to be added >in the above manner for --- >1/78,1/81,1/82,.. etc.? > > >Dan >
.
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