Re: x^3-x=6*y^3




Pubkeybreaker wrote:
>
> It is a curve of genus 2, and hence has finitely many
> integer solutions by Siegel's theoem. It also has
> finitely many rational solutions by Falting's thm.

Genus 1, because x^3 - x = N.y^3 is equivalent to
x^2 - 1 = N.x^2.(y/x)^3, i.e. - N.(y/x)^3 + 1 = (1/x)^2

.



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