Re: infinity



Ross A. Finlayson wrote:
>> So: well-order the reals.
>

Jonathan Hoyle wrote:
> Sigh. Didn't I do this one already? Here it is again <grin>:
>
> Take any arbitrary 1-1 mapping F from the reals R to the power set of
> natural numbers P(N). By the Axiom of Choice, we know we can
> well-order P(N), so take any such well-ordering, <=. Define a <=
> operation (obviously different from the standard one) on R such that
> for a,b in R, a <= b whenever F(a) <= F(b). You have now well-ordered
> R. Creating F and well ordering P(N) are left as exercises. :-)

To well-order P(N), we can define a '<' relation between members
of P(N):

a. {} < {i, ...} for all i in N;
The empty set is less than any set with one or more members.

b. {i, ...} < {j, ...} if i < j for all i,j in N;
Any set with a least element i is less than any other set with a
least element j if i < j.

c. {i, j, ...} < {i, k, ...} if {j, ...} < {k, ...}
for all i,j,k in N and i < j and i < k;
For two sets both having a least member i, the first set is less
than the second if the set formed by removing i from the first set
is less than the set formed by removing i from the second set
(this is a recursive definition that makes use of the previous rules).

So all the the members of P(N) can be ordered using the '<' relation
defined above.

.



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