Re: commutator subgroup...closed



It's in the definition itself : you should perhaps see a definition of a
group generated by a set.

If G is a group and X is a nonempty subset of G, then the subgroup <X>
generated by X consists of all finite products ((a_1)^n_1) ...
((a_t)^n_t) , (a_i in X, n_i in Z)
.



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