Re: Tricky equation!

In article <1128969775.766135.113590@xxxxxxxxxxxxxxxxxxxxxxxxxxxx> rastablasta70@xxxxxxxxxxx writes:
>Hi all, recently had to solve the following and ive been having
>problems! would be very gratefull if someone could explain how to get
>the answer.
>
>by choosin a suitable numerical value for A, show that tan 15' is a
>root of hte quadratic equation t(squared) + 2(root)3 -1=0
>
>Many Thanks

The consequent of "show that" does not mention A.
Look at the problem more carefully.

You can get tan(15 degrees) if you know
sin(15 degrees) and cos(15 degrees).
Try to get these in terms of what you already know.


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