Re: Cantor



You have missed something. But a quick read of internet sources about
Cantor's argument shows that you've missed the same thing a alot of
other people. I think we need to clarify some subtleties.

You need to create a distinction between:

complete infinities
- Cantor's complete infinite set of the reals

potential infinity
- This is what you are talking about when you say that we have a
list of numbers that
can be of any length

Cantor was not talking about "any list of you can produce" we was
talking about "*the* complete list of reals"

These two lists have quite different properties. Cantor had to
postulate a complete list of the reals in order to show that this lead
to a contradiction.

Otherwise if allowed ourselves to use the "list of any length" approach
then we can very quickly show that for any list of integers we can
produce an integer not on that list. But this argument is clearly
unhelpful.

Have a look around at the arguments surround potential and actual
infinities, the concerns and difficulties are far from simple.

.



Relevant Pages

  • Re: Cantor
    ... Cantor was not talking about "any list of you can produce" we was ... These two lists have quite different properties. ... infinities, the concerns and difficulties are far from simple. ...
    (sci.math)
  • Re: MY LIST of the subsets of N
    ... This looks very much like when I attempted to prove Cantor wrong. ... > PROGRAM OUTPUT: ... > Cantor was restricted to considering lists of subsets which have the ... > the process he proved that the the cardinality of the set of subsets ...
    (sci.math)
  • Re: Of course Cantors diagonlisation is ok was Re: Wheres respect?....
    ... Cantor's proof shows that all lists of real numbers are ... A construction which proves there is a ... Let's remember that the Cantor construction is to construct ... That number has a rule for the n-th digit. ...
    (sci.math)
  • Re: MY LIST of the subsets of N
    ... > LET CANTOR APPLY HIS DIAGONAL PROCEEDURE TO MY LIST: ... > Cantor was restricted to considering lists of subsets which have the ... > the process he proved that the the cardinality of the set of subsets ... The main problem with any algorithm to enumerate a set is ...
    (sci.math)
  • Re: MY LIST of the subsets of N
    ... Allowing for this;The set of all odd numbers is in my list. ... Newsgroups: sci.math "For any sets A, B: IfA is a proper subset of ... > This looks very much like when I attempted to prove Cantor wrong. ... >> Cantor was restricted to considering lists of subsets which have the ...
    (sci.math)