Re: Radical Expression For cos(2*pi/29)

"M.A.Fajjal" <h2maf@xxxxxxxxx> wrote in message news:21554396.1129835070178.JavaMail.jakarta@xxxxxxxxxxxxxxxxxxxxxxxxx
> cos(2*pi/29)=1/2*(2+n1+(2-n1^2+n2)^(1/2))^(1/2)

I tried your formulas. I get

cos(2*pi/29)=.97662055571008668320822796287786...
1/2*(2+n1+(2-n1^2+n2)^(1/2))^(1/2)=1.03760055035243493433378328702353...

The formulas for cos(2*pi/7) and sin(2*pi/7) appear fine, but the
result for cos(2*pi/29) did not work for me.

m1=-1610.0362505673123271
m2=1178.0961514450481025
m3=-2051.4114633777357754
g1=2.5263214622687833168-.931504089781744561*i
g2=1.3754569175121094885-2.3147609526834700852*i
g3=.5889649441305952901+2.6273789781044615735*i
g4=.5889649441305952901-2.6273789781044615735*i
g5=1.3754569175121094885+2.3147609526834700852*i
g6=2.5263214622687833168+.931504089781744561*i
n1=1.2116409496889965987
n2=.6667016863521067713
w=.62348980185873353053+.7818314824680298087*i


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