Re: infinity ...

David R Tribble said:
> David R Tribble:
> >> Obviously, you do not understand.
> >> My set is:
> >> S = {0, 2^0, 2^2^0, 2^2^2^0, 2^2^2^2^0, ...}
> >> S = {0, 1, 2, 4, 16, 65536, ...}
>
> Albrecht Stortz:
> > I don't know what kind of math you apply here. Tribble-O-Math?
> > I don't want discuss your very interesting system.
> > Look at my starting posting if you want to know in what I'm interested
> > to discuss.
> > Start a new thread if you search for people which want talk about
> > Tribble-O-Math.
>
> It's obvious that you don't understand simple arithmetic. 2^x is 2
> raised to the x power. 2^2^x is 2^(2^x), using ordinary arithmetic.
>
> I'm giving you set S so that you can tell us whether it is an
> infinite set or not. You said:
>
> >> either there are infinite natural numbers or there is no infinite set.
>
> So I'm giving you set S, which obviously does not contain any
> infinite numbers. So by your rule, the set is finite, right?
>
>
If it doesn't contain any infinite members, it's not infinite. Those terms
differ by more than a constant finite amount, but rather a rapidly growing
amount greater than 1. There is no way you have an infinite number of them
without achieving infinite values within the set.
--
Smiles,

Tony
.

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