Re: Nearing breakthrough...need magic :-)

"Erik" <Erik99@xxxxxxxxx> wrote in message
news:1131066657.345014.30590@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> Does anyone know if there's a mathmatical (as opposed to computational)
> way to find an integer value for m and e, such that for a given odd
> integer n,
>
> mn = (2^e)-1
>
> OR
>
> mn = (2^e)+1
>
> in other words, find a multiple of n that is equal to a power of two,
> minus (or plus) one?
>
> (i'm guessing no).

How about:

e = (n-1)!
m = (2^e - 1) / n

Regards,
Mike.



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