Re: Well Ordering the Reals
- From: "Randy Poe" <poespam-trap@xxxxxxxxx>
- Date: 15 Nov 2005 14:48:59 -0800
Tony Orlow wrote:
> David R Tribble said:
> > David R Tribble wrote:
> > >> All members of *N will map to subsets of *N. That's not the problem.
> > >> There are subsets of *N that are not mapped by any member of *N.
> > >> That's the problem.
> > Tony Orlow wrote:
> > > Oh. Can you name one, please?
> >
> > I already have, several times. You just keep ignoring them.
> >
> No you haven't. You have spooken in vague terms, claiming that N indexes the
> bits of each element in *N
What is vague about "there is one bit for every n in N"?
> when in fact you need bits with actually infinite
> bit positions to achieve the infinite values in *N.
This claim is either (a) wrong or (b) unjustified, since you haven't
defined
what you mean by this set *N. The only definition I've seen so far
is that "*N is the set of bit strings whose bits are labelled with
elements
of *N". From that I conclude that *N is the empty set, with no bits,
and that there is no need for infinite labels.
- Randy
.
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