Re: Well Ordering the Reals

On Mon, 21 Nov 2005 13:27:13 -0800, imaginatorium wrote:

>
> boink wrote:
>> On Mon, 21 Nov 2005 15:46:29 -0500, Tony Orlow wrote:
>>
>> >
>> >>
>> >> Given N = {1,2,3,...}, let S_n = {1,2,3,...,n} = {x in N: 1 <= x <= n}.
>> >>
>> >> For all n in N there is m in N\S_n,
>> >> so for all n in N, size(N) > size(S_n) = n.
>> > No, here is your mistake. size(N) >= size(S_n) = n. The size is a member of the
>> > set.
>> >
>>
>> In any event,
>> N is infinite.
>> S_n is finite.
>>
>> This is very simple. I don't understand how you don't understand.
>
> Dear mr boink,
>
> I see you must be new around here.
>

heh.

i'm more of an occasional lurker or something...

also, i'm trying to be as un-mean as possible.

> Luv,
> Chief Imaginator
> http://imaginatorium.org
> (Haven't you got boink.com or anything?)

.

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