Re: how to factor a^n - b^n
- From: "Stephen J. Herschkorn" <sjherschko@xxxxxxxxxxxx>
- Date: Sat, 26 Nov 2005 12:41:07 -0500
Kenneth Bull wrote:
How does one factor a^n - b^n where n is a natural number?
a^n - b^n = (a - b) sum(k=0..n-1, a^(n-k-1) b^k)
-- Stephen J. Herschkorn sjherschko@xxxxxxxxxxxx Math Tutor on the Internet and in Central New Jersey and Manhattan
.
- References:
- how to factor a^n - b^n
- From: Kenneth Bull
- how to factor a^n - b^n
- Prev by Date: Re: Undecidability
- Next by Date: Re: Defining "<" for the rationals
- Previous by thread: Re: how to factor a^n - b^n
- Next by thread: Re: how to factor a^n - b^n
- Index(es):