Re: Hard problem
- From: john_ramsden@xxxxxxxxxxxxxx
- Date: 1 Dec 2005 13:58:30 -0800
Peper wrote:
>
> three _positive_ real numbers a,b,c with
> ab + bc + ca = 3
>
> prove that:
> a^3 + b^3 + c^3 + 6abc >= 9
>
> Any hints how to do that?
>
> --
> Best Regards,
> Peper
Yes - Use the Rusin method to express it as a sum of squares.
Should be pretty straightforward (chortle).
.
- References:
- Hard problem
- From: Peper
- Hard problem
- Prev by Date: Re: are rational exponents defined for negative bases?
- Next by Date: Re: Cardinality of the surreals
- Previous by thread: Re: Hard problem
- Next by thread: Re: Hard problem
- Index(es):
Relevant Pages
|
