Re: vector analysis

From: Adam Burley <burl2k@xxxxxxxxxxx>
Date: Mon, 05 Dec 2005 15:17:10 EST

A is a vector, so divA is a scalar, so QdivA is also a scalar, by ordinary scalar multiplication.

To prove it, write div(QA) as delta_{p,q} (d/d(x_p)) (QA)_q, calculate that by the product rule, and then rewrite it as the RHS.
.

References:
- vector analysis
  - From: Robert

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