Re: Math Problem
- From: jeyadev@xxxxxxxxxxxxxxxxxxxxxxxx (Surendar Jeyadev)
- Date: 7 Dec 2005 20:53:38 GMT
In article <1133901268.145507.126240@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
Randy Poe <poespam-trap@xxxxxxxxx> wrote:
>
>PaulHjelmstad wrote:
>> This is one that a piano student of mine was working on.
>> She apparently solved it, but I don't get it.
>>
>> Given the parabola y=x^2, find two lines perpendicular to one another that are both tangent to this parabola.
>>
>> (The tangent lines must have slope y=|2x|, right?
>
> 2x
>
>The slope of y = x^2 is negative on the left of the y-axis.
>
>> And perpendicular lines are nx, -(x/n) right? So I don't see
>> how this problem could have any solutions
>
>Any x1, x2 such that (2x1)(2x2) = -1 will constitute a solution.
>
>For instance x1 = 1, x2 = -1/4. The tangent at x = 1 is the line
^^^^^^^^^
x2 = -1/(4 x1)
>y = 2x -1, with slope 2. The tangent at x2 = -1/4 is the line
^^^^^^^^^
Works as x1 = 1!
>16y + 8x = -1, with slope -1/2.
>
> - Randy
>
--
Surendar Jeyadev jeyadev1@xxxxxxxxxxxxx
The 1 in the email address is fake
.
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- Math Problem
- From: PaulHjelmstad
- Re: Math Problem
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- Math Problem
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