Re: central forces
- From: Robert Low <mtx014@xxxxxxxxxxxxxx>
- Date: Mon, 19 Dec 2005 20:23:51 +0000
Tony wrote:
Hi, I hope someone can spare a few moments to help with a problem
Suppose, F(r) = -m(36/r^2 + 27/r^3)
If this is supposed to be a force, shouldn't there be a vector somewhere?
and it's initial position and velocity is given by
What is 'it'?
theta(0)=0
x(0) = 2e{r} v(0) = 3e{theta}
Show that u(theta) = 1/4[1 + cos(theta/2)]
What is u?
If you actually state your question, you might have more luck getting somebody to help you with it.
But, guessing that there's an invisible e_r in your F, and that u is 1/r, then what you want to do is to get a differential equation for the orbit in the form du/dtheta = "something". This is a completely standard trick which you should find in any mechanics book which covers the usual inverse square law force, so I'll leave you to find it for yourself. .
- Follow-Ups:
- Re: central forces
- From: William Elliot
- Re: central forces
- References:
- central forces
- From: Tony
- central forces
- Prev by Date: Re: inner product space
- Next by Date: Re: inverse and derivative of a function
- Previous by thread: central forces
- Next by thread: Re: central forces
- Index(es):
Relevant Pages
|
