random variables - simple questions
- From: Tobin Fricke <fricke@xxxxxxxxxxxxxxxx>
- Date: Sat, 14 Jan 2006 23:59:43 -0800
I am having some trouble with some simple questions concerning random variables.
The first: Suppose we have a random variable X with zero mean and variance sigma^2. What is the probability distribution of Y = X^2?
Here's my argument:
P[Y=y] = P[X^2 = y] = P[|X| = sqrt(y)] = P[X=sqrt(y) OR X=-sqrt(y)] = P[X=sqrt(y)] + P[X=-sqrt(y)] = 2 P[X=sqrt(y)]
We have for P[X=x] the usual normal (gaussian) distribution:
P[X=x] = 1/(sigma Sqrt(2Pi)) Exp[-x^2/(2 sigma^2)]
so I expect that I can just substitute in x=sqrt(y):
P[Y=y] = 2 P[X=sqrt[y]] = 2/(sigma Sqrt(2Pi)) Exp[-y/(2 sigma^2)]
But that is not right. It doesn't integrate to unity and it doesn't give the correct expectation value for Y.
Using the cumultative distribution function I follow a similar argument and get the answer:
P[Y=y] = 1/(sigma Sqrt(2 Pi y)) Exp[-y/(2 sigma^2)]
(Notice that there is a 1/sqrt(y) in there, and no factor of 2 out front.)
I believe that answer is correct (it passes my checks)... but where does the logic fail in the argument using probability density functions?
The second question: Suppose we have independent random variables X and Y, both normally distributed with zero mean and unit variance. Define U=aX+bY and V=cX+dY. Show that U and V are independent if and only if (a,b) and (c,d) are orthogonal, i.e. ac+bd=0.
I'm not sure what to use as the test for independence here. I know <UV>=<U><V> is a <i>necessary</i> condition for the independence of U and V, but it is not in general sufficient. (Though I read somewhere that it is, in the case of normally distributed random variables??)
thanks, Tobin
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