Re: Summation, modulo and decimal

> Yikes. What is it you are doing, explicitly?

>The easiest way to do what you want, if what I think you want is
>indeed what you want, is to simply multiply both numbers by 10^6, do
>the modulus, and then divide the result by 10^6. That is, do 147536
>mod 101110, which is 46426; then divide the result by 10^6 to get
>0.046426

Given a number n (real, periodic or not), say, 23.38276345 I want to
"transform" the value to 01.10010111 . The question isn´t to convert
to a binary value or change the base. So I used the (n mod 2) to get
the 0´s and 1´s and then shift to left one digit (multiply by 10).
The "mechanic" of it using Summation that is trapping me. I have not
found a way to shift the number to left while keeping the old value or
just to let it go to the left k places and then get back k places to
the right again without changing the inicial value n.

.

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