Re: Cantorian pseudomathematics
Randy Poe wrote:
Han de Bruijn wrote:
Jiri Lebl wrote:
[ ... ] Thus from your responses it is clear that you don't know for
example what continuum means (you think you know what it means, but
that's a different matter, Tony Orlow also thinks he knows what he's
talking about)
Pfff ...
- Light is a bunch of photons (discrete)
Yes.
AND it is a wave (continuous)
No.
Yes.
- A fluid is a bunch of molecules (discrete)
Yes.
AND it is continuous (see e.g. the Navier Stokes equations)
No. You claim to be trained in physics. If you were, you would
have seen the distinction made between "exact" and "approximation",
and for every approximation you would have seen conditions
carefully spelled out under which that approximation worked
and for which it didn't work.
No. The discrete is as much an approximation as the continuous.
Nothing - I repeat: absolutely NOTHING - is "exact" in physics.
It is kind of a running joke in physics that the engineers take
the approximations and use them as if they are exact, even
when leaving the domain of applicability.
If we don't leave the domain of applicability, are you still joking?
I doubt you had very good training.
Remember us when you walk over that bridge. And it doesn't collapse.
- A tube bundle in a heat exchanger (discrete) may be ALSO continuous
- The prime numbers are discrete
Yes.
but they may be considered continuous
No.
Yes. And it gives the outcome that 1/ln(x) is the probability density
that a natural is a prime. An that is valid everywhere, i.e. not only
asymptotically. It's the same technique as used with heat exchangers.
Weird, huh?
Do you agree with the above?
Whose position do you think you are describing with the
above list of contradictory statements?
Mine, of course. As always.
Han de Bruijn
.
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(sci.physics.relativity) |
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