Re: probability question
- From: briggs@xxxxxxxxxxxxxxxxx
- Date: 24 Jan 2006 12:15:32 -0600
In article <43d664f9$0$45117$892e7fe2@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx>, "Ben Luden" <invalid@xxxxxxxxxxx> writes:
>
> "Mkajuma" <mboghom@xxxxxxxxxxxxxx> wrote in message
> news:xYsBf.1666$wk5.1476@xxxxxxxxxxxxxxxx
>>I guess it is uniform.
>> Thanks.
>
> It has to be uniform, Poisson doesn't apply in this case.
> 1st guy is there 1/6 of the time, and the second is there 1/6 of the time.
> So the chances of meeting are 1/36 or about 2.8%
Probability is (roughly) 1/6 for the 1st guy to arrive while the 2nd
guy is waiting.
Probability is (roughly) 1/6 for the 2nd guy to arrive while the 1st
guy is waiting.
Those cases are disjoint. Either will result in a successful meeting.
The probabilities add. They do not multiply.
This line of attack seems fraught with peril. The edge cases (what
happens when someone arrives between 1:50 and 2:00) seem particularly
tricky to get right with this method of analysis.
.
- Follow-Ups:
- Re: probability question
- From: Ben Luden
- Re: probability question
- References:
- probability question
- From: Mkajuma
- Re: probability question
- From: gwlucky
- Re: probability question
- From: Mkajuma
- Re: probability question
- From: Ben Luden
- probability question
- Prev by Date: Re: JSH: Keep it simple
- Next by Date: Re: JSH: Keep it simple
- Previous by thread: Re: probability question
- Next by thread: Re: probability question
- Index(es):
Relevant Pages
|