Existence of pdf and mgf
- From: Olw <anders_REMOVE@xxxxxxxxxxx>
- Date: Fri, 27 Jan 2006 16:43:20 +0100
Hello,
I have some struggles understanding existence implications between the moment generating function and a probability distribution.
Going from a pdf / cdf to an MGF is OK, the MGF M(t)exists if the expectation E(e^{tx}) exist at some neighborhood of 0.
The other way, however. Given a function claiming to be an MGF, for example M(t) = t or M(t)=t/(1-t), for |t|<1. How can one know if it exists a corresponding pdf?
Obviously, if one calculate M''(t) and evaluate it at 0 and finds it negative, then M(t) can not be an MGF for a probability distrubution. What I am looking for is a general rule to check this.
Also, say that one can decide that an MGF is valid, i.e., there is a corresponding pdf. Then the pdf can be found by inverse Laplace transforming M(-t). Is this in convenient also for distribution that can take negative values? Or does it exist any clever tricks for finding the pdf?
Thanks,
Olw .
- Follow-Ups:
- Re: Existence of pdf and mgf
- From: Robert Israel
- Re: Existence of pdf and mgf
- Prev by Date: Re: An error in Coxeter's regular polytopes?
- Next by Date: Re: Contradicrtion-free mathemattics (The new nonstandard analysis
- Previous by thread: JSH: Math as a religion
- Next by thread: Re: Existence of pdf and mgf
- Index(es):
Relevant Pages
|
Loading