Re: Binomial distribution question

First, thank you for your help.

AHH! That makes sense! I see where I was getting confused by. I just
plug the answer into mathematica and got 8% as an answer. If you want I
can still go through each term separately, but I am not sure how to
make mathematica print out each term of the sum so I will isntead
justselect a few key ones, found below.

32!/((32 - 27)! 27! )* (.927)^27* (1 - .927)^(32 - 27)=0.0539231

32!/((32 - 5)! 5! )* (.073)^5 * (1 - .073)^(32 - 5)=0.0539231

32!/((32 - 26)! 26! )* (.927)^26* (1 - .927)^(32 - 26)=0.0191087

32!/((32 - 6)! 6! )* (.073)^6 * (1 - .073)^(32 - 6)=0.0191087

32!/((32 - 0)! 0! )* (.927)^0* (1 - .927)^(32 -
0)=4.229913865563006`*^-37

32!/((32 - 32)! 32! )* (.073)^32 * (1 - .073)^(32 -
32)=4.229913865563006`*^-37

.

Relevant Pages

  • Re: Binomial distribution question
    ... > AHH! ... > plug the answer into mathematica and got 8% as an answer. ... U.S. Court of Appeals to review three issues ...
    (sci.math)
  • Re: A difficult hamiltonian problem
    ... Are there any stable fix points? ... but using Mathematica or Maple this is a very quick ... Prev by Date: ...
    (sci.math)
  • Root condition for polynomials
    ... If it can be done on mathematica what are the ... Regards, ... Terry ... Prev by Date: ...
    (sci.math.num-analysis)
  • Re: Sum of Gaussian functions
    ... To my mind (and with the help of mathematica) the expression ... of this nearly-constant periodic function could be: ... Valeri ... Prev by Date: ...
    (sci.math.num-analysis)
  • Re: Challenging ODE
    ... >ODE, or try running it through Mathematica: ... Maple says: ... Prev by Date: ...
    (sci.math)