Re: Contradicrtion-free mathemattics (The new nonstandard analysis

From: matthias@xxxxxxxxxxx
Date: 29 Jan 2006 18:13:21 -0800

E. E. Escultura
> Is R* non-associative Not at all because d* + x = x

Assuming your equation holds, I may add -x to both sides to obtain
d* = 0. But you have said that d* is not 0. This is yet another
contradiction in what you have posted here.

.

References:
- Re: Contradicrtion-free mathemattics (The new nonstandard analysis
  - From: Robert J. Kolker
- Re: Contradicrtion-free mathemattics (The new nonstandard analysis
  - From: E. E. Escultura
- Re: Contradicrtion-free mathemattics (The new nonstandard analysis
  - From: matthias

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