Re: Help with recursion

From: "robert.w.adams@xxxxxxxxxxx" <robert.w.adams@xxxxxxxxxxx>
Date: 30 Jan 2006 23:59:45 -0800

OK, if I do that then I get

sum(2 to n) x_sub_n = sum(2 to n) x_sub(n-1) + sum(2 to n) K/log(n)

and if I subtract sum(2 to n) x_sub(n-1) from both sides;

x_sub_n = sum(2 to n) K/log(n)

Is there a closed-form solution for sum(2 to n) K/log(n) ?

Bob Adams

.

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