Re: Card pairing probabilities


"Phil Freedenberg" <pfreedenberg@xxxxxxxxxxx> wrote in message
news:21169342.1138690532120.JavaMail.jakarta@xxxxxxxxxxxxxxxxxxxxxxxxx
> Suppose a standard deck of 52 cards is randomized.
>
> How would you calculate the probability that no
> adjacent cards have the same value (e.g., pair of
> treys, pair of Kings, etc.)
>
> What is the expected number of such pairs in a deck?
>
> phil

Simulation run 1,000,000 shows 51,076 shuffles without a pair adjacent
"" "" 156,414 " " with any 1
pair adjacent
"" "" 235,142 " " with any 2
pair adjacent

You can have more faith in the sim if 2nd & 3rd results agree with
Stephen's reasoning.
HTH Mick


.

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