Re: Power of 2 divisible by 3

Shmuel (Seymour J.) Metz wrote:
> In <1138647285.161615.119780@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>, on
> 01/30/2006
>    at 10:54 AM, XleonardXcobetX@xxxxxxxxx said:
>
> >I cannot seem to find a power of 2 divisible by 3.
>
> That's because you're working in Z, the ring of integers. Try it in,
> e.g., Z/5, where 2^3 is 3 (8=3+5).

In Z/5Z, already 2 is divisible by 3.  No need to raise to a power...

-- chip

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