Re: linear operator, determinant
- From: Sean Holman <holmansf@xxxxxxxxx>
- Date: Wed, 15 Feb 2006 19:01:56 EST
I haven't worked out the details, but I seem to recall that the determinant is the product of the eigenvalues. I wonder if you can write the eigenvalues for M_B in terms of the ones for B.
.
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