L(G) and L(G')
Given a CFG G where epsilon is in L(G), how would you create a new
grammar L(G' = L(G) - epsilon? I know there is a method that allows you
to change a grammar G where epsilon is not part of L(G) and you can get
a equivalent grammar G' having no epsilon production. The question
arises when you have epislon as part of the lanaguage. Thank you for
help in adanced.
.
Relevant Pages
- Re: An example LL(K) language that is not LL(K-1) ?
... that needs k tokens to disambiguate. ... I think your example grammar is an LLgrammar,and after left ... C:= epsilon ... the language is not LL. ...
(comp.compilers) - Re: OpenToken: Handling the empty word token
... Because OpenToken uses Ada types to build the grammar, ... need an explicit Epsilon token: ... It appears that OpenToken uses an LL-derived parsing scheme. ... it's important to note that LL parsing cannot include epsilon tokens and ...
(comp.lang.ada) - Re: OpenToken: Handling the empty word token
... The parser is an LALR parser. ... what the dragon book has to say about epsilon handling. ... if there are already some sort of reserved words in the grammar source). ...
(comp.lang.ada) - Re: CFG for L(G) and L(G)
... to change a grammar G where epsilon is not part of Land you can get ... If a production has more than two symbols on the RHS, ... Now remove all empty productions. ...
(comp.theory) - CFG for L(G) and L(G)
... Given a CFG G where epsilon is in L, how would you create a new ... to change a grammar G where epsilon is not part of Land you can get ... arises when you have epislon as part of the lanaguage. ...
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