Re: Difficult question
- From: klaus hoffmann <nospam@xxxxxxxxxxxx>
- Date: Sat, 25 Feb 2006 17:24:19 +0100
Proginoskes wrote:
Whatever5k@xxxxxx wrote:The former replies make it likely that he was asking a question posed in the german competition "bundeswettbewerb mathematik"
Hi everybody,
I am trying to prove that:
x* + y* = 4(x*y + xy* + 1)
has no solutions for odd x and y.
I have no idea what your equation is asking, because there are
unreadable characters in your post. (I have replaced them with
asterisks.)
You should use the carat (^) for exponents, so that your equation
becomes
x^? + y^? = 4 (x^? y + x y^? + 1)
If the ?'s are even, then you can take both sides modulo 4, since x^n =
1 mod 4 if n is even. Then you get the equation
1 + 1 = 0 * N = 0 mod 4,
which is a contradiction.
--- Christopher Heckman
please don't give the solution before the deadline, the first of march
Klaus
.
- References:
- Difficult question
- From: Whatever5k
- Re: Difficult question
- From: Proginoskes
- Difficult question
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