Re: Bitwise OR and AND without bitwise operators....
- From: "CelticDaddio" <spamtrap@xxxxxxxxxxxxxxx>
- Date: 28 Feb 2006 12:27:04 -0800
Is this correct? Bit k, of n would be
m = n/k, m-((m/2)*2)
So could I do this
int testValue = 41;
for(int nBit = 0; nBit < numberOfBits; nBit++) {
m = testValue/nBit;
int bitSet = m-((m/2)*2)
}
CD
.
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