Re: Limit without L'Hospital
- From: Virgil <ITSnetNOTcom#virgil@xxxxxxxxxxx>
- Date: Sun, 05 Mar 2006 21:09:27 -0700
Hi!
How do you solve without using L'Hospital:
lim{x->oo} ( (e^(1/x) - e^(1/(x+1)) )/(1/(3*x^2) )
?
Best Regards,
Andrew
Little-oh
In article <1141605608.879843.145300@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
"Andrew" <scootertuner@xxxxxxx> wrote:
Hello Virgil!
Can you be more explicit?
Andrew
As x -> +oo, one has
e^(1/x) = 1 + 1/x + + o(1/x)
e^(1/(x+1)) = 1 + 1/(x+1) + + o(1/x)
where o(f(x)) is a term which goes to zero more rapidly than f(x), so
(e^(1/x) - e^(1/(x+1)) )/(1/(3*x^2) = 3*x/(x+1) + o(1)
.
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