charactristic function and integration
- From: "Gary Weselle" <weselle_g@xxxxxxxxxxx>
- Date: Thu, 9 Mar 2006 13:56:08 -0800
Hi
Does the statement;
A set is pavable it it has a well-defined volume ( i.e., if its
characteristic function is integrable).
Implies that the domain of the integration is bounded? It seams to me that
this is the only requirement left for a characteristic function to imply a
well-defined volume.
Am I correct? If not why?
Thanks
.
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