Re: My problem in Maxima: The if-statement


<earthnut@xxxxxx> skrev i en meddelelse
news:1141866153.936689.283250@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
0^x = 0 for x <> 0

sorry, 0^x = 0 for x > 0, but for x < 0 it is not a number


I agree. 0^0 or 0^(negative value) also cause error messages in Maxima.

It can be a little confusing sometimes. 0^0 '=' 0^(-0) '=' 1/ (0^0), which
again causes 'division by zero'. 0^0 can't really be defined, not even with
this rule. One could think that 0^0 simply equals 0, but then the question
is: Is it 0^0 '=' 0 or is it 1/(0^0) '=' 1/0 -> infinite?

On the statement, that I wrote:

f(x):= if x>1 then 1 else 0;

I found this solution:

h(x):= 1/2 * signum(x-1) + 1/2;

(On signum(x); in Maxima: x=-1 for x<0, x=0 for x=0 and x=1 for x>0)

So that problem doesn't matter so much anymore.But I need this if-statement
for something else, because this f(x) was just an example.

PC


.

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