Re: How do I do this problem without a calculator?
- From: quasi <quasi@xxxxxxxx>
- Date: Thu, 16 Mar 2006 02:46:35 -0500
On 15 Mar 2006 23:29:46 -0800, "Foster Bell" <bell3774@xxxxxxxxx>
wrote:
One approach, not discussed by other notes in this thread so
far, would be to consider the computation modulo 2 and again
modulo 11. You can then piece together the answer modulo
22 from the separate answers for 2 and 11.
This approach is very enticing, but I don't know how to "piece
together" the results.
6^19 mod 2 is 0
6^19 mod 11 is 2
Now I know that the answer is 6^19 mod 22 is 2, but I know that from
doing the problem, not from the facts above. Is there a generic rule to
use?
Yes, you can use the Chinese Remainder Theorem.
However the numbers here are so small, I would just do it by
inspection.
Let 6^19 = x mod 22 where 0 <= x <= 21
6^19 = x mod 22 ==> 6^19 = x mod 2 => x = 0 mod 2
6^19 = x mod 22 ==> 6^19 = x mod 11 => x = 2 mod 11
In the range 0 to 21 inclusive, only two numbers satisfy x = 2 mod 11,
namely x = 2 and x = 13, but only x = 2 also satisfies x = 0 mod 2.
Therefore x = 2.
quasi
.
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